Calculate the cell e.m.f. at `25^(@)C` for the cell: `Mg(s)|Mg^(2+)(0.01M)||Sn^(2+)(0.1M)|Sn(s)` Given `E_(Mg^(2+)//Mg)^(@)=-2.34V,E_(Sn^(2+)//Sn)^(@)=-0.136V,1F=96,500" C "mol^(-1)` Calculate the maximum work that can be accomplished by the operation of this cell.

Calculate the cell e.m.f. at `25^(@)C` for the cell: `Mg(s)|Mg^(2+)(0.

1.	Calculate the cell e.m.f. at `25^(@)C` for the cell: `Mg(s)\|Mg^(2+)(0.01M)\|\|Sn^(2+)(0.1M)\|Sn(s)` Given `E_(Mg^(2+)//Mg)^(@)=-2.34V,E_(Sn^(2+)//Sn)^(@)=-0.136V,1F=96,500" C "mol^(-1)` Calculate the maximum work that can be accomplished by the operation of this cell.
Answer» Correct Answer - `E_(cell)^(@)=2.50V,w_(max)=425.372kJ` `Mg+Sn^(2+)toMg^(2+)+Sn,E_(cell)^(@)=-0.136-(-2.34)=2.204V` `E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Mg^(2+)])/([Sn^(2+_)]), thereforeE_(cell)=2.204-(0.0591)/(2)"log"(0.01)/(0.1)=2.500V` `w_(max)=-DeltaG^(@)=nFE_(cell)^(@)=2xx96500xx2.204=425372J` (Note that `w_(max)` is related to `E_(cell)^(@)` and not `E_(cell)`).

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