Calculate the concentration of nitric acid in moles per litre in a sam

1.	Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 g mL-1 and the mass percent of nitric acid in it being 69%.
Answer» 69% HNO₃ by mass means 69 g of HNO₃ is present 100 g of solution. Volume of solution = Mass/Density = 100/1.41 = 70.9 mL^-3 Molar mass of HNO₃ = 1 + 14 + 48 = 63 u Moles of HNO₃ = 69/63 = 1.09 Concentration = {1.09 x 1000}/{70.9} = 15.37 moles per litre

Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 g mL-1 and the mass percent of nitric acid in it being 69%.

Answer»

69% HNO₃ by mass means 69 g of HNO₃ is present 100 g of solution.

Volume of solution = Mass/Density = 100/1.41 = 70.9 mL^-3

Molar mass of HNO₃ = 1 + 14 + 48 = 63 u

Moles of HNO₃ = 69/63 = 1.09

Concentration = {1.09 x 1000}/{70.9} = 15.37 moles per litre