InterviewSolution
Saved Bookmarks
| 1. |
Calculate the degree of dissociation of 0.02 M acetic acid at 298K, given that `lambda_(CH_(3)COOH)=11.7ohm^(-1)cm^(2)"mol"^(-1)` `lambda_((CH_(3)COO^(-)))=40.9ohm^(-1)cm^(2)"mol"^(-1)` `lambda(H^(+))^(@)=349.1ohm^(-1)cm^(2)"mol"^(-1)`A. 0.06B. 0.015C. 0.03D. 0.09. |
|
Answer» Correct Answer - C `DeltaG^(@)=-nFE^(@)=-2xx96500xx(-0.76)` `=146680J=146.68kJ`. |
|