Calculate the emf of the following cell at 298K `Fe_((s))|Fe^(2+)(0.001M)||H^(+)(1M)|H_(2(g))(1" bar"),Pt_((s))` (Given `E_(cell)^(@)=+0.44V`)

Calculate the emf of the following cell at 298K `Fe_((s))|Fe^(2+)(0.00

1.	Calculate the emf of the following cell at 298K `Fe_((s))\|Fe^(2+)(0.001M)\|\|H^(+)(1M)\|H_(2(g))(1" bar"),Pt_((s))` (Given `E_(cell)^(@)=+0.44V`)
Answer» Correct Answer - 0.53 V `Fe+2H^(+)toFe^(2+)+H_(2)`, `E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Fe^(2+)])/([H^(+)]^(2))=0.44-(0.0591)/(2)"log"(0.001)/((1)^(2))`

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Calculate the emf of the following cell at 298K `Fe_((s))|Fe^(2+)(0.001M)||H^(+)(1M)|H_(2(g))(1" bar"),Pt_((s))` (Given `E_(cell)^(@)=+0.44V`)

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