1.

Calculate the energy associated with the first orbit if He+.What is the radius of this orbit?

Answer»

Energy E = -13.6 x \(\frac{z^2}{n^2}\)eV

For He+ z = 2

Value of n for first orbit = 1

\(\therefore\) E = -13.6 x \(\frac{(2)^2}{(1)^2}\)

= -54.4 eV

Radius of this orbit,

rn\(\frac{52.9(n^2)}{z}\)

r1\(\frac{52.9\times1^2}{2}\)

= 26.45 pm

= 0.2645 Å



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