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Calculate the energy associated with the first orbit if He+.What is the radius of this orbit? |
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Answer» Energy E = -13.6 x \(\frac{z^2}{n^2}\)eV For He+ z = 2 Value of n for first orbit = 1 \(\therefore\) E = -13.6 x \(\frac{(2)^2}{(1)^2}\) = -54.4 eV Radius of this orbit, rn = \(\frac{52.9(n^2)}{z}\) r1 = \(\frac{52.9\times1^2}{2}\) = 26.45 pm = 0.2645 Å |
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