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calculate the energy assoclated with the first orbit of `He^(+)` . What is the radius of this orbit? |
Answer» `E_(n)=-((2.18xx10^(-18)J)Z^(2))/n^(2)"atom"^(-1)` for `He^(+),n=1 , Z=2` ` E_(1) =-((2.18xx10^-18 J)(2^(2)))/1^(2)=-8.72xx10^(-18)J` the radius of the orbit is given by equation (2.15) `r_(n) = ((0.0529nm)n^(2))/Z` since n=1 , and Z = 2 ` r_(n) =((0.0529 nm)1^(2))/2 = 0.02645 nm ` |
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