InterviewSolution
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InterviewSolution
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Calculate the equivalent resistance between the points `A and B` in the circuits shown in (Fig. 3.19) (a) and (Fig. 3.19) (b). . |
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Answer» Correct Answer - (a) `4 Omega` (b) `6 Omega`. (a) Two resistances `(6 Omega,6 Omega)` in the upper arm are in series and their resultant resistance `= 6 Omega + 6 Omega = 12 Omega`. Further, `12 Omega and 6 Omega` (in the lower arm) are in parallel. The resultant resistance of `12 Omega and 6 Omega` in parallel is `(12 xx 6)/(12 + 6) Omega = 4 Omega`. (b) The resultant resistance of `6 Omega,6 Omega` which are in parallel in the first loop is `(6 xx 6)/(6 + 6) Omega = 3 Omega`. Similarly, the resultant resistance in the second loop is also `3 Omega`. Since the two loops are in series, the total resistance between A and B is `3 Omega + 3 Omega = 6 Omega`. |
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