1.

Calculate the log_(10)of the ratio of the catalysed and uncatalysed rate constants at 25^(@)C. If at this temp. the energy of activation of a catalysed reaction is 162 kJ and for the uncatalysed reaction the value is 350 kJ. (Assume frequency factor is same for both reaction).

Answer»

`30.94`
`32.94`
`35.94`
`40.94`

Solution :`K = Ae^(Ea//RT) implies LOG K = log A-(Ea)/(2.303RT)`
`log K_("cat".) = log A - (162 xx 10^(3))/(2.303 RT)` …………(i)
`log K_("uncat".) = log A - (350 xx 10^(3))/(2.303RT)` ……….(ii)
`eq^(N) (i) - eq^(n) (ii)`
`log K_("cat".) - log K_("uncat".) = ((350-162)xx10^(3))/(2.303 RT)`
`log(K_("cat".))/(K_("uncat".)) = 32.94`.


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