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Calculate the magnitude of ring strain energy in (kJ/mol) of cyclopropane from the following data Delta_(f)H[C_(3)H_(6)(g)]=55,Delta_(f)H[C(g)]=715,Delta_(f)H[H(g)]=220, BE(C-C)=355,BE(C-H)=410 ( all in kJ/mol ) : |
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Answer» SOLUTION :[0115] Given ![]() `DeltaH_(4)=-B.E. (3C-C+6C-H)+`RING strain energy (RSE) `=DeltaH_(1)-DeltaH_(2)-DeltaH_(3)` `R.S.E=DeltaH_(1)=DeltaH_(1)-DeltaH_(2)-DeltaH_(3)`+B.E.(3C-C+6C-H) `=55-2145-1320+(3xx355+6xx410)` `=115kJ//mol` |
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