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Calculate the mass of Calcium that will contain the same number of atoms as are present in 3.2 gm of Sulphur. [Atomic masses : S = 32, Ca = 40] |
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Answer» 32 gm of sulphur contain = 6.023 x 1023 atoms 3.2 gm of sulphur contain = (6.023 x 1023)/32 x 3.2 = 6.023 x 1022 Now, 6.023 x 1023 atom of calcium have mass = 40 g 6.023 x 1022 atoms of calcium have mass = 40/(6.023 x 1023) x (6.023 x 1022) = 4 g Hence, the mass of calcium is 4 g. |
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