Calculate the mass of sodium acetate (CH3COONa) required to make 500 m

1.	Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol-1.
Answer» Mass of sodium acetate required to make 1000 mL of 1 M aqueous solution = 82.0245 g Mass of sodium acetate required to make 500 mL of 1 M aqueous solution = {82.0245 x 500}/{1000} = {82.0245}/{2} g Mass of sodium acetate required to make 500 mL of 0.375 molar aqueous solution = {82.0245 x 0.375}/{2} = 15.38 g

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol-1.

Answer»

Mass of sodium acetate required to make 1000 mL of 1 M aqueous solution = 82.0245 g

Mass of sodium acetate required to make 500 mL of 1 M aqueous solution

= {82.0245 x 500}/{1000} = {82.0245}/{2} g

Mass of sodium acetate required to make 500 mL of 0.375 molar aqueous solution

= {82.0245 x 0.375}/{2} = 15.38 g