1.

Calculate the mass per cent of each element present in the molecule of calcium carbonate.​

Answer»

ANSWER :)The mass of calcium in this compound is equal to 40.1 grams because there's one atom of calcium PRESENT and calcium has an atomic mass of 40.1 amu. The MOLAR mass of the compound is 100.1 grams. Using the handy equation above, we get:The mass of calcium in this compound is equal to 40.1 grams because there's one atom of calcium present and calcium has an atomic mass of 40.1 amu. The molar mass of the compound is 100.1 grams. Using the handy equation above, we get:Mass percent = 40.1 G Ca⁄100.1 g CaCO3 × 100% = 40.1% CATHE mass of calcium in this compound is equal to 40.1 grams because there's one atom of calcium present and calcium has an atomic mass of 40.1 amu. The molar mass of the compound is 100.1 grams. Using the handy equation above, we get:Mass percent = 40.1 g Ca⁄100.1 g CaCO3 × 100% = 40.1% CaOur result means that 40.1% of the mass in the calcium carbonate supplement is CAUSED by calcium. To find the total mass of calcium in the supplement, we find 40.1% of one gram to get a final answer of 0.401 grams of calcium.



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