Calculate the molality of 98% H2SO4 aq solution by mass.

1.	Calculate the molality of 98% H2SO4 aq solution by mass.
Answer» \tMolarity ( mole/L)- Assume an identical solution with volume 1L. Now, the total mass of this solution as per the data =1.84\xa0×1000= 1840 g. The amount of (mass) H2SO4 =1840\xa0×0.98=1803.2 g. Number of moles= 1803.2/98= 18.4 moles. Theerfore, Molarity =18.4 M\tMolality (mole(solute)/kg(solvent))- Assume an identical solution wherein there is 1000g of solvent. Thus here we will have the mass of H2SO4= 49000g (since, in this solution solute (H2SO4)is 98% and solvent thus is 2%). So, number of moles of H2SO4= 49000/98= 500. So , Molality = 500 mole/kg.

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