Calculate the no of ions of AlF3 in two moles?

1.	Calculate the no of ions of AlF3 in two moles?
Answer» A 0.21 M solution of ALF contains 0.21 moles of molecules for each liter of solution. In this problem we have only 65.5 mL (0.0655 L) of solution, so the number of moles is 0.21M×0.0655L=0.01376mol .Ionization of each AlF unit produces one FLUORIDE ion ( F− ), so the number of moles of fluoride ions is the same, 0.01376mol . As the other contributors have POINTED out, the correct FORMULA for aluminum fluoride is AlF3 , and in this case, each formula unit would produce three F− ions.Finally, to obtain the actual number of ions, we multiply by Avogadro's number:0.01376mol×6.022×1023mol−1=8.28×1021or, in the case of AlF3 ,3⋅0.01376mol×6.022×1023mol−1=2.48×1022

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