Calculate the normality of a 200 ml of H2SO4 solution which when treated with excess of BaCl2 solution precipitates 2.33 g of BaSO4.

Calculate the normality of a 200 ml of H2SO4 solution which when treat

1.	Calculate the normality of a 200 ml of H2SO4 solution which when treated with excess of BaCl2 solution precipitates 2.33 g of BaSO4.
Answer» ormality of any acid or base will be EQUAL to gram-equivalent desolve in given volume N = gram-equivalent/ volume(lt.) When two or more compounds or elements react together their gram-equivalent will be equal in simple WAY, 10 gm-eq of an acid will react completely with 10 gm-eq of base, In given problem, gm-eq. of H2SO4 = NV(lt.) and N = nM where, M = molarity and n = BASICITY or acidity of an acid or base. gm-eq of H2SO4 = 10020.20.001 =0.04gm-eq gm-eq of NaOH = 1000.210.001 =0.02 REMAINING gm-eq of H2SO4 = 0.04–0.02 0.02gm-eq Now, gm-eq. = NV = 0.02 TOTAL volume =200ml = 0.2 lt. N0.2 = 0.02 = 0.1N