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Calculate the normality of a solution containing 13.4 g fo sodium oxalate in 100mL solution. |
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Answer» Normality = `("wt. in g/eq. wt")/("vol. of solution in litre")` Here, eq. wt. of `Na_(2)C_(2)O_(4)=134//2=67` so `N=(13.4//67)/(100//1000)=2N` |
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