1.

Calculate the normality of a solution containing 13.4 g fo sodium oxalate in 100mL solution.

Answer» Normality = `("wt. in g/eq. wt")/("vol. of solution in litre")`
Here, eq. wt. of `Na_(2)C_(2)O_(4)=134//2=67`
so `N=(13.4//67)/(100//1000)=2N`


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