Calculate the number of `kw-h` of electricity is necessary to produce `1.0` metric ton `(1000 kg)` of aluminium by the Hall process in a cell operating at `15.0 V`.

Calculate the number of `kw-h` of electricity is necessary to produce

1.	Calculate the number of `kw-h` of electricity is necessary to produce `1.0` metric ton `(1000 kg)` of aluminium by the Hall process in a cell operating at `15.0 V`.
Answer» `Al^(3+)+3e rarr Al` Eq. of `Al, (w)/(E) = (i.t)/(96500)` `:. i.t = (1000 xx 10^(3) xx 96500)/(27//3) [E_(Al) = 27//3]` `i.t = 107.22 xx 10^(8)` ampere-sec or coulomb `E = "Coulomb" xx "volt" = 107.22 xx 10^(8) xx 15.0` `= 1.61 xx 10^(11) J-sec` or `E = 1.61 xx 10^(11) "watt-sec"` `= (1.61 xx 10^(11))/(10^(3)) xx (1)/(3600) kW-hr` `= 4.47 xx 10^(4) kW-h`

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Calculate the number of `kw-h` of electricity is necessary to produce `1.0` metric ton `(1000 kg)` of aluminium by the Hall process in a cell operating at `15.0 V`.

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