Calculate the oxidation number of suplhur in the folowing molecules and ions: `(i) H_(2)SO_(4) , (ii) Na_(2)SO_(4), (iii) SO_(4)^(2-), (iv)S_(2)O_(4)^(2-)`

Calculate the oxidation number of suplhur in the folowing molecules an

1.	Calculate the oxidation number of suplhur in the folowing molecules and ions: `(i) H_(2)SO_(4) , (ii) Na_(2)SO_(4), (iii) SO_(4)^(2-), (iv)S_(2)O_(4)^(2-)`
Answer» (i) S in `H_(2)SO_(4)` Let the oxidation number of s in `H_(2)SO_(4)` be x Write the oxidation number of each atom above its symbol `H_(2)^(+1) overset(x)S O_(4)^(-2)` Calculate the sum of the oxidation numbers of all the atoms Since `H_(2)SO_(4)` is a neutral molecule, the sum of oxidation numbers must be zero. (ii) S in `Na_(2)SO_(4)` Let the oxidation number of S in `Na_(2)SO_(4)` be x Write the oxidation number of each atom above its symbol `overset(+1)Na_(2) overset(x)S overset(-2)O_(4)` Calculate the sum of the loxidation numbers of all the atoms 2(+1) +x+4(-2)=2+x-8=x-6 since `Na_(2)SO_(4)` is a neutral molecule, the sum of the oxidation numbers must be zero x-6=0 or x=+6 (iii) S in `SO_(4)^(2)` ion Let the oxidation number of S in `SO_(4)^(2)` ion be x write the oxidatioin numbers of both the atoms above their symbols calculate the sum of the oxidation numbers of both the atoms `x+4(-2)=x-8` Since `SO_(4)^(2)` ion is an anion the sum of the oxidation numbers must be -2 x-8=-2 or x= -2+=+6 (iv) S in `S_(2)O_(4)^(2)`ion "Let the oxidation number of S in `S_(2)O_(4)^(2)` ion be x. Write the oxidation numbers of both atoms above their symbols" `overset(x)S_(2) overset(-2)O_(4)` "Calculate the sum of oxidation number of both the atoms" `2(x)+4(-2)=2x-8` Since `S_(2)O_(4)^(2)` "is an anion the sum of the oxidation numbers must be" -2 `2(x) -8=-2 or 2 x =- 2 + 8 = 6 or x =6//2 =+3`

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Calculate the oxidation number of suplhur in the folowing molecules and ions: `(i) H_(2)SO_(4) , (ii) Na_(2)SO_(4), (iii) SO_(4)^(2-), (iv)S_(2)O_(4)^(2-)`

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