InterviewSolution
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InterviewSolution
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Calculate the pH of a solution obtained by mixing equal volumes of the solutions with pH = 3 and pH = 5. |
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Answer» pH = 3 means `[H^(+)]=10^(-3)M and pH = 5` means `[H^(+)]=10^(-5)`M. On mixing equal volumes, in the final solution, `[H^(+)]=((10^(-3)+10^(-5))/(2)) = (10^(-3)(1+10^(-2)))/(2) = (1.01xx10^(-3))/(2) = 0.505xx10^(-3) M = 5.05 xx 10^(-4) M ` `:. pH = - log (5.05xx10^(-4))=4-0.7033~~3.3` |
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