1.

Calculate the rate at which water flows thorugh a capillary tube of length 0.5 m with an internal radius of 1 mm. Coefficient of viscosity is 1.3 xx 10^(-3) kg//m^(-s). The pressure head is 20 cm of water .

Answer»

Solution :`P= (20-10^(-2) xx 1000 xx 9.8) Nm^(-2) , r = 10^(-3)m , l= 0.5 m`
`ETA = 1.3 xx 10^(-3)Kg//m^(-s) ,` From Poiseuill.s formula `V = (PI Pr^4)/(8 etal)`
`=(3.14xx20 xx 10^(-2) xx 1000 xx 9.8 xx (10^(-3))^4)/(8xx1.3 xx 0.5) = 1.2 xx 10^(-6) m^3 s^(-1)`.


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