Calculate the rate at which water flows thorugh a capillary tube of length 0.5 m with an internal radius of 1 mm. Coefficient of viscosity is 1.3 xx 10^(-3) kg//m^(-s). The pressure head is 20 cm of water .

Calculate the rate at which water flows thorugh a capillary tube of le

1.	Calculate the rate at which water flows thorugh a capillary tube of length 0.5 m with an internal radius of 1 mm. Coefficient of viscosity is 1.3 xx 10^(-3) kg//m^(-s). The pressure head is 20 cm of water .
Answer» <html><body><p></p>Solution :`P= (20-10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) xx 1000 xx 9.<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>) Nm^(-2) , r = 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)m , l= 0.5 m` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/eta-446786" style="font-weight:bold;" target="_blank" title="Click to know more about ETA">ETA</a> = 1.3 xx 10^(-3)Kg//m^(-s) ,` From Poiseuill.s formula `V = (<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> Pr^4)/(8 etal)` <br/>`=(3.14xx20 xx 10^(-2) xx 1000 xx 9.8 xx (10^(-3))^4)/(8xx1.3 xx 0.5) = 1.2 xx 10^(-6) m^3 s^(-1)`.</body></html>