Calculate the stability constant of the complex `[Zn(NH_(3))_(4)]^(2+)` formed in the reaction `Zn^(2+)+4NH_(4)hArr[Zn(NH_(3))_(4)]^(2+)`. Given that `E_(Zn^(2+)//Zn)^(@)=-0.76V and E_((Zn(NH_(3))_(4)]^(2+))^(@)//Zn,4NH_(3))^(@)=-1.03V`

Calculate the stability constant of the complex `[Zn(NH_(3))_(4)]^(2+)

1.	Calculate the stability constant of the complex `[Zn(NH_(3))_(4)]^(2+)` formed in the reaction `Zn^(2+)+4NH_(4)hArr[Zn(NH_(3))_(4)]^(2+)`. Given that `E_(Zn^(2+)//Zn)^(@)=-0.76V and E_((Zn(NH_(3))_(4)]^(2+))^(@)//Zn,4NH_(3))^(@)=-1.03V`
Answer» We are given `Zn^(2+)(aq)+2e^(-)hArrZn(s)" "E^(@)=-0.76V` `[Zn(NH_(3))_(4)]^(2+)+2e^(-)hArrZn(s)+4NH_(3),E^(@)=-1.03V` To get the overal reaction, we should write `Zn^(2+)(aq)+2e^(-)hArrZn(s)," "E^(@)=-0.76V` `Zn(s)+4NH_(3)hArr[Zn(NH_(3))_(4)]^(2+)+2e^(-)," "E^(@)=1.03V` Adding, we get `E_(cell)^(@)=1.03-0.76=0.27V` `E_(cell)^(@)=(0.0591)/(n)logK` or `logKk=(0.27xx2)/(0.0591)=9.1371` or `K="Antilog "9.1371=1.371xx10^(9).`

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Calculate the stability constant of the complex `[Zn(NH_(3))_(4)]^(2+)` formed in the reaction `Zn^(2+)+4NH_(4)hArr[Zn(NH_(3))_(4)]^(2+)`. Given that `E_(Zn^(2+)//Zn)^(@)=-0.76V and E_((Zn(NH_(3))_(4)]^(2+))^(@)//Zn,4NH_(3))^(@)=-1.03V`

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