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Calculate the total pressure in a 10 L cylinder which contains 0.4 g of helium, cylinder. Assume ideal behaviour of gases.`(R=0.082 L atm K6(-1)mol^(-1))` |
Answer» Total no. of moles of all gases(n)`=(0.4)/(4)+(1.6)/(32)+(1.4)/(28)=0.2` Volume of the gasesour mixture (V)=10 L Temperature (T)=27+273=300 K, R=0.082 L atm `K^(-1)mol^(-1)` As gases have behaviour, PV=nRT or `P=(nRT)/(V)=(0.2xx0.082xx300)/(10)=0.492 atm` `"Partial pressure of helium "=(0.4//4)/(0.2)xx0.492=0.246 atm` |
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