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Calculate the vapour density of a gas, 12.8g of which occupies 10L at a pressure of 750 mm at 27°C. |
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Answer» V.D. = 15.92Explanation:We know : Vapour DENSITY ( V.D. ) = W / 2 × ( R T / P V ) We have given : W = 12.8 gT = 27 C = 27 + 273 K = 300 KP = 750 / 760 atmV = 10 LValue of R = 0.081 L-atm mol⁻¹ K⁻¹Putting values we get : V.D. = ( 12.8 × 0.082 × 300 ) / ( 750 / 760 × 10 × 2 ) V.D. = ( 6.4 × 8.2 ) ( 15 / 76 × 10 ) V.D. = 15.92Hence we get required ANSWER. |
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