Calculate the volume occupied by 4.045 x 1023 molecules of oxygen at 2

1.	Calculate the volume occupied by 4.045 x 1023 molecules of oxygen at 27°C and having a pressure of 700 torr.
Answer» Number of molecules = 4.045 x 10²³ p = 700 torr = 700/760 atm T = 27 + 273 = 300 K R = 0.082 litre atm K^-1 mol^-1 n = {No. of molecules}/{6.023 x 10²³} = {4.045 x 10²³}/{6.023 x 10²³} = 0.672 mol Now, pV = nRT or V = nRT/P or, V = {(0.672 mol) x (0.082 litre atm.mol^-1 K^-1)(300 K)}/{(700/760 atm)} = 17.95 litres

Calculate the volume occupied by 4.045 x 1023 molecules of oxygen at 27°C and having a pressure of 700 torr.

Answer»

Number of molecules = 4.045 x 10²³

p = 700 torr = 700/760 atm

T = 27 + 273 = 300 K

R = 0.082 litre atm K^-1 mol^-1

n = {No. of molecules}/{6.023 x 10²³}

= {4.045 x 10²³}/{6.023 x 10²³} = 0.672 mol

Now, pV = nRT or V = nRT/P

or, V = {(0.672 mol) x (0.082 litre atm.mol^-1 K^-1)(300 K)}/{(700/760 atm)}

= 17.95 litres