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Calculate the work done. (a) Along path AB(b) Along path BC (c ) Along path CA (d) For the whole cycle. The indicator diagram, between P and V, is as shown.

Answer» <html><body><p>&lt;<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>&gt;</p>Solution :Word done is positive when gas expands and <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> when gas contracts. <br/> In P-V diagram, P is represented along y-axis and V is taken along x-axis. Work done is positive if the cycle is clockwise and work done is negative if cycle is anticlockwise. <br/> (a) Work done `= P xx "<a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in volume" Delta V` <br/> `W_(<a href="https://interviewquestions.tuteehub.com/tag/ab-360636" style="font-weight:bold;" target="_blank" title="Click to know more about AB">AB</a>) = 20 xx (3-2) = 20 xx 1 = 20 J` <br/> (b) `W_(BC) = "Pressure" xx (3-3) = "zero"`. <br/> As there is no change of volume. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ) `W_(CA)` = It is negative because volume decreases. <br/> = -Area of CALMC= -Area of (ABC + ABML) <br/> `= -((1)/(2) xx 1 xx 20 + AB xx BM)` <br/> `= -(10 + 1 xx 20) = -30 J` <br/> (d) For whole cycle, <br/>work done = -area of `Delta ABC = -(1 xx 20)/(2)` <br/> `:.` work done for whole cycle = -10 J <br/> Note : For whole cycle, we may consider <br/> `W_(AB) + W_(BC) + W_(CA)` also.</body></html>


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