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InterviewSolution
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Calculate the work done during compression of 2 mol of an ideal gas from a volume of `1m^(3)` to `10 dm^(3)` 300 K against a pressure of 100 KPa .A. `-99 kJ`B. `+99 kJ`C. `+22.98 kJ`D. `-22.98 kJ` |
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Answer» Correct Answer - B Work done during compression, `W = p_("ext") DeltaV` Given, `p_(ext) = 100 K Pa, T = 300 K` `DeltaV = V_(2) - V_(1)` `= (10 - 1) dm^(3) = 9 dm^(3)` `= 0.99 m^(3)` `:. W = - 100 Kpa (0.99)m^(3)` `=99 kJ`. |
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