Cesium chloride forms a body-centred cubic lattice. Cesiumm and chloride ions are in contact along the body diagoanl of a cell. The length of the side of the unit cell is `412 pm` and `Cl^(Θ)` ion has a radius of `181` pm. Calculate the radius of `Cs^(o+)` ion.

Cesium chloride forms a body-centred cubic lattice. Cesiumm and chlori

1.	Cesium chloride forms a body-centred cubic lattice. Cesiumm and chloride ions are in contact along the body diagoanl of a cell. The length of the side of the unit cell is `412 pm` and `Cl^(Θ)` ion has a radius of `181` pm. Calculate the radius of `Cs^(o+)` ion.
Answer» Body diagonal `= sqrt((sqrt2a)^(2) + a^(2)) = sqrt3a` `= 2(r_(Cs^(o+)) + r_(Cl^(Θ)))` `= 1.732 xx 412` pm `= 713.58` pm `:. r_(Cs^(o+)) = (713.58)/(2)-r_(Cl^(Θ))` `= (356.79 - 181)` pm `= 175.8` pm

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Cesium chloride forms a body-centred cubic lattice. Cesiumm and chloride ions are in contact along the body diagoanl of a cell. The length of the side of the unit cell is `412 pm` and `Cl^(Θ)` ion has a radius of `181` pm. Calculate the radius of `Cs^(o+)` ion.

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