1.

Check whether the value given in the brackets is a solution to the given equation or not :(a) n + 5 = 19 (n = 1)(b) 7n + 5 = 19(n = -2)(c) 7n + 5 = 19 (n = 2)(d) 4p – 3= 13 (p = 1)(e) 4p – 3 = 13 (p = -4)(f) 4p – 3 = 13 (p = 0)

Answer»

(a) 1 + 5 ≠ 19
6 ≠ 19
∴ LHS ≠ RHS to
∴ n = 1 is not a solution to the given equation n + 5 = 19.

(b) 7 × -2 + 5 = 19
-14 + 5 = 19
-9 = 19
LHS ≠ RHS
∴ n = -2 is not a solutions the given equation 7n + 5 = 19 (n = 2)
7 × 2 + 5 = 19
14 + 5 = 19
19 = 19
LHS = RHS
∴ n = 2 is a solution to the given equation 7n + 5 = 19

(c) 7 × 2+5 = 19
14 + 5 = 19
19 = 19
LHS = RHS
∴ n = 2 is a solution to the given equation 7n + 5 = 19.

(d) 4(1) – 3 = 13
4 – 3 = 13
1 ≠ 13
LHS ≠ RHS
∴ p = 1 is not a solution to the given equation 4p – 3 = 13.

(e)  4(-4) – 3 = 13
– 16 – 3 = 13
-19 ≠ 13
LHS ≠ RHS
∴ p = -4 is not a solution to the given equation 4p – 3 = 13.

(f)  4(0) – 3 = 13
0 – 3 = 13
– 3 ≠ 13
LHS ≠ RHS
∴ p = 0 is not a solution to the given equation 4p – 3 = 13.


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