Circuit shows the method of Measurement of low resistance by Ammeter-Voltmeter method. The measured resistance Rm for the given Circuit is _________(a) Rx + Rv(b) \(\frac{R_x^2}{R_x + R_v}\)(c) \(\frac{R_v^2}{R_x + R_v}\)(d) \(\frac{R_x R_v}{R_x + R_v}\)This question was posed to me in a job interview.The above asked question is from Advanced Problems on Measurement of Low Medium and High Resistance in chapter Measurement of Resistance of Electrical Measurements

Circuit shows the method of Measurement of low resistance by Ammeter-V

1.	Circuit shows the method of Measurement of low resistance by Ammeter-Voltmeter method. The measured resistance Rm for the given Circuit is _________(a) Rx + Rv(b) \(\frac{R_x^2}{R_x + R_v}\)(c) \(\frac{R_v^2}{R_x + R_v}\)(d) \(\frac{R_x R_v}{R_x + R_v}\)This question was posed to me in a job interview.The above asked question is from Advanced Problems on Measurement of Low Medium and High Resistance in chapter Measurement of Resistance of Electrical Measurements
Answer» CORRECT OPTION is (d) \(\frac{R_x R_v}{R_x + R_v}\) The BEST EXPLANATION: Measured resistance Rm = \(\frac{V_x}{I_A} = \frac{V_x}{I_v + I_R}\) \(\frac{I_v}{V_x} =\frac{1}{R_v}\) And \(\frac{I_R}{V_x} = \frac{1}{R_X}\) So, Rm = \(\frac{R_x R_v}{R_x+R_v}\).

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