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Compare the radial length of Serond orbit of h atom with the same of fourth orbit of He+ ion. |
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Answer» It is given that the quantisation RULE followed in aliens' planet is as follows:mvr= 4πnh The change in quantisation rule will not AFFECT the energy difference.The energy difference (in EV) is given by the expression =E n −E n′ =−13.6×[ n 2 1 − n ′2 1 ]We need to find the energy difference between fourth and second orbits.E 4 −E 2 =−13.6[ 4 2 1 − 2 2 1 ]E 4 −E 2 =−13.6×[0.0625−0.25]=−13.6×(−0.1875)=2.55 eVHence, the energy difference between fourth and second orbits for H ATOM is 2.55 eVExplanation:hope it helps |
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