Conductivity of an aqueous solution of `0.1M HX` (a weak mono-protic acid) is `5 xx 10^(-4) Sm^(-1)` Given: `^^_(m)^(oo) [H^(+)] = 0.04 Sm^(2) mol^(-1): ^^_(m)^(oo) [X^(-)] = 0.01 Sm^(2)mol^(-1)` Find `pK_(a)[HX]`

Conductivity of an aqueous solution of `0.1M HX` (a weak mono-protic a

1.	Conductivity of an aqueous solution of `0.1M HX` (a weak mono-protic acid) is `5 xx 10^(-4) Sm^(-1)` Given: `^^_(m)^(oo) [H^(+)] = 0.04 Sm^(2) mol^(-1): ^^_(m)^(oo) [X^(-)] = 0.01 Sm^(2)mol^(-1)` Find `pK_(a)[HX]`
Answer» Correct Answer - 9 `HX hArr H^(+) +X^(-)` `0.1(1-alpha) 0.1 alpha 0.1 alpha` `K_(a) = (0.1alpha^(2))/(1-alpha)` `alpha =(^^_(m))/(^^_(m)^(oo)) = 0.05` `^^_(m) = (K)/(M) = (5 xx 10^(-4)Sm^(-1))/((0.1mol)/(10^(-3)m^(3)))`

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Conductivity of an aqueous solution of `0.1M HX` (a weak mono-protic acid) is `5 xx 10^(-4) Sm^(-1)` Given: `^^_(m)^(oo) [H^(+)] = 0.04 Sm^(2) mol^(-1): ^^_(m)^(oo) [X^(-)] = 0.01 Sm^(2)mol^(-1)` Find `pK_(a)[HX]`

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