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Consider a P-V diagram in which the path followed by one mole of perfect gas in a cylindrical container as shown in Fig a) Find the work done when the gas is taken from state 1 to state 2. b) What is the ratio of temperature T_(1)//T_(2), if V_(2)=2V_(1) ? c) Given the internal energy for one mole of gas at temperature T is (3//2) RT, find the heat supplied to the gas when it is taken from state 1 to 2, with V_(2)=2V_(1) .

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :a) Work done by the <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> (Let` PV^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>//2)=A`) <br/> `DeltaW=int_(V_(1))^(V_(2))pdv=A int_(V_(1))^(V_(2))(dV)/sqrtV=A[(sqrtV)/(1//2)]_(V_(1))^(V_(2))=2A(sqrtV_(2)-sqrtV_(1))=2P_(1)V_(1)^(1//2)[V_(2)^(1//2)-V_(1)^(1//2)]` <br/> b) <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> `T =pV//nR=A/(nR).sqrtV` <br/> Thus `T_(2)/T_(1)=sqrt(V_(2)/V_(1))=sqrt2` <br/> c) Then, the change in internal energy <br/> `DeltaU=U_(2)-U_(1)=3/2R(T_(2)_T_(1))=3/2RT_(1)(sqrt2-1)` <br/> `DeltaW=2AsqrtV_(1)(sqrt2-1)=2RT_(1)(sqrt2-1)` <br/> `DeltaQ=(7//2)RT_(1)(sqrt2-1)`</body></html>


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