1.

Consider that an ideal gas (n moles) is expanding in a process given by P=f(V), which passes through a point(V_(0),P_(0)). Show that the gas is absorbing heat at (P_(0),V_(0))if the slope of the curve P=f (V) is larger than the slope of the adiabat passing through (P_(0), V_(0)).

Answer»

Solution :Slope of `P=f(V)`, curve at `(V_(0) , P_(0))= f(V_(0))`
Slope of ADIABAT at `(V_(0) P_(0))`
`=k(-gamma) V_(0)^(-1-gamma)= -gammaP_(0)//V_(0)`
Now heat absorbed in the process P = f(V)
`dQ = dU +dW = nC_(v)dT +PdV`
Since `T=(1//nR) PV=(1//nR) V f(V)`
`dT = (1//nR) [f(V)+Vf.(V)]dV`
Thus `(dQ)/(dV)underset(V=V_(0))("" ) =(CV)/(R )[f(V_(0))+V_(0)f.(V_(0))]+f(V_(0))`
`=[(1)/(gamma-1)+1]f(V_(0)) +(V_(0)f.(V_(0)))/(gamma-1)`
`=(gamma)/(gamma-1)P_(0) +(V_(0))/(gamma-1)f.(V_(0))`
Heat is absorbed when `dQ//dV GT 0` when gas EXPANDS, that is when
`gammaP_(0) +V_(0) f.(V_(0)) gt 0`
`f.(V_(0)) gt -gammaP_(0)//V_(0)`


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