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Consider the cell reaction `:` `Mg(s)+Cu^(2+)(aq) rarr Cu(s) +Mg^(2+)(aq)` If `E^(c-)._(Mg^(2+)|Mg(s))` and `E^(c-)._(Cu^(2+)|Cu(s))` are `-2.37` and `0.34V`, respectively. `E^(c-)._(cell)` isA. `-2.71V`B. `2.71V`C. `-2.03V`D. `2.03V` |
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Answer» Correct Answer - B Cell reaction is `Mg(s)+Cu^(2)+(aq)rarrCu(s)+Mg^(2+)(aq)` Half reaction at LHE , i.e., oxidation `MghArrMg^(2+)+2e^(-)` Half reaction at LHE, i.e., Reduction `Cu^(2+)(aq)+2e^(-)hArrCu(s)` Now, `E_(LHE)^(@)=E_(Mg^(2+//Mg))^(@)=-237V` `E_(RHE)^(@)=E_(Cu^(2+)//Cu)^(@)=+0.34V` `therefore E_( "cell")^(@)=E_(RHE)^(@)-E_(LHE)^(@)` `=0.34-(-2.37)=2.71V` |
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