Consider the compounds, `BCl_(3)` and `"CCl"_(4)` . How will they behave with water ? Justify .

Consider the compounds, `BCl_(3)` and `"CCl"_(4)` . How will they beha

1.	Consider the compounds, `BCl_(3)` and `"CCl"_(4)` . How will they behave with water ? Justify .
Answer» The B atom in `BCl_(3)` has only six electrons in the valence shell and hence is an electron-deficient molecule. It easily accepts a pair of electrons donated by water and hence `BCl_(3)` undergoes hydrolysis to form boric acid `(H_(3)BO_(3))` and HCl. `BCl_(3) rarr + 3H_(2)O rarr H_(3)BO_(3) + 3HCl` In contrast, C atom is `"CCl"_(4)` has 8 electrons in the valence shell. Therefore, it is an electron-precise molecule and hence neither accepts nor donates a pair of electrons. In other words , it does not accept a pair of electrons from `H_(2)O` molecule and hence `"CCl"_(4)` does not under go hydrolysis in water.

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Consider the compounds, `BCl_(3)` and `"CCl"_(4)` . How will they behave with water ? Justify .

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