Consider the following array initialisation, int ar[5]={-2,-4,-6,2,4};

1.	Consider the following array initialisation, int ar[5]={-2,-4,-6,2,4}; If first element of array is stored at 2050 and size of int is 4, nd the output of the following.1. cout<< ar+(ar+3); 2. cout<< ar+*(ar+4);
Answer» 1. ar = -2 (ar + 3) = 2 (fourth element) Hence ar + (ar + 3) = -2 + 2 = 0 Hence output is 0 2. Here ar = 2050 (starting address) and * (ar + 4) = (2050 + 44) = (2050+16) = (2066) = 4 (fth element) Hence ar + * (ar + 4) = 2050 + 4 = 2054

Consider the following array initialisation, int ar[5]={-2,-4,-6,2,4}; If first element of array is stored at 2050 and size of int is 4, nd the output of the following.1. cout<< ar+(ar+3); 2. cout<< ar+*(ar+4);

Answer»

*ar = -2

*(ar + 3) = 2 (fourth element)

Hence *ar + *(ar + 3) = -2 + 2 = 0

Hence output is 0

Here ar = 2050 (starting address)

and * (ar + 4)

= *(2050 + 4*4)

= *(2050+16)

= *(2066)

= 4 (fth element)

Hence ar + * (ar + 4)

= 2050 + 4

= 2054