InterviewSolution
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InterviewSolution
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Consider the reaction `{:((R)-CH_(3)CHICH_(2)CH_(3)+^(137)T^(-),rarrCH_(3)CHICH_(2)CH_(3),,,),(alpha_(obs)=-15.90^(@),"containing" 2%137T^(-),,,),(,alpha_(obs)=-15.26^(@),,,):}` The percentage of racemic from in the product isA. `10%`B. `8%`C. `4%`D. `12%` |
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Answer» Correct Answer - C Note that replacement of `I` with `.^(137)I` does not change he sign or value of the rotation. The optical purity of the recovered iodide is `(15.26//15.90)(100%) = 96%`. Hence `4%` of the iodide is racemic. This means thet `2%`, (the same percentage that contains isostopic `I)`. has been converted to the `(S)` configuraiton. It is concluded that every reaction with `.^(137)T^(-)` resulted in an inversion at chiral carbon. |
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