InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Consider the situation shown in fig. The two slits `S_(1)` and `S_(2)` placed symmetrically around the central line are illuminated by monochromatic light of wavelength `lambda`. The separation between the slit is d. The ligth transmitted by the slits falls on a screen `S_(0)` placed at a distance D form the slits. The slit `S_(3)` is at the central line and the slit `S_(4)` is at a distance z from `S_(3)` Another screen `S_(c)` is placed a further distance D away from `S_(c)` Find the ratio of the maximum to minimum intensity observed on `S_(c)` If `z = (lambda D)/(2 d)`A. 1B. `1//2`C. `3//2`D. 2 |
|
Answer» Correct Answer - a `z = (lambda D)/(2 d)` At `S_(4): (Delta x)/(4) = (z)/(D)` `implies Delta x = (lambda D)/(2 d) = (lambda)/(2)` Hence, minima at `S_(4)` and maxima at `S_(3)` (intensity `4 I_(0)`). Hence, `(I_(max))/(I_(min)) = 1` |
|