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Construct a triangle PQR whose perimeter is 12 cm and the lengths of whose sides are in the ratio 3:2:4. |
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Answer» Step 1: A line AB = 12 cm is drawn. Step 2: It is divided into (3+2+4) = 9 parts. Step 3: BA9 is joined. Step 4: From A3(at 3 points distance from A), a line is drawn parallel to BA9 to AB at Q and from A5(at 2 points distance from A3), a line is drawn parallel to BA9 to AB at R. Step 5: With R as centre and RB as radius, an arc is drawn and named it as P. Step 6: With Q as centre and AQ as radius, an arc is drawn to cut the other arc at P. Step 7: PQ and PR are joined and the triangle PQR is formed. 3x+2x+4x = 12 9x = 12 x = 12/9 x = 1.33 cm The sides are 4,2.7,5.3 cm |
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