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Copper gives two oxides. On heating `1g` of each in hydrogen, we get `0.888 g and 0.798 g` of the metal respectively. Show that these results are in agreement with the Law of Multiple Proportions. |
Answer» Let us fix `1g` of copper as the fixed weight in the two oxides In the first oxide Weight of copper `= 0.888 g` Weight of oxygen `= 1-0.888 = 0.112g` Now, `0.888g` of copper combine with oxygen `= 0.112 g` `:. 1.0 g` of copper combine with oxygen `= (0.112)/(0.888)g=0.126 g` In the second oxide Weight of copper `= 0.798 g` Weight of oxygen `= 1-0.798 = 0.202 g` `0.798 g` of copper combine with oxygen `=0.202 g` `1.0 g` of copper combine with oxygen `= (0.202)/(0.798)g=0.253 g` Ratio by weight of oxygen which combine with `1g` of copper in the two oxides is `0.126 : 0.253 or 1:2` As the ratio is simple whole number in nature, the law of Multiple Proportions is proved. |
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