copper gives two oxides .on heating 1gram of each in hydrogen,we get 0.888gram and0.798gram of the metal respectively .show that these results are in agreement with the law of multiple proportion

copper gives two oxides .on heating 1gram of each in hydrogen,we get 0

1.	copper gives two oxides .on heating 1gram of each in hydrogen,we get 0.888gram and0.798gram of the metal respectively .show that these results are in agreement with the law of multiple proportion
Answer» Let the two OXIDES by cu be A and BOxide A:-Mass of Cu in 1g=0.888gMass of O in 1g=1−0.888=0.112gOxide B:-Mass of Cu in 1g=0.799gMass of O in 1g=1−0.799=0.201gIn oxide A:- 0.112× 0.8881 =0.126gIn oxide B:- 0.201× 0.7991 =0.252gSo, 0.126 and 0.252 are the figure of Cu combined with oxygen in both the oxides.∴ Ratio=0.126:0.252or 1:2∴ This is a simple whole ratio that shows that ARGUMENT with the LAW of MULTIPLE PROPERTIES.