`CuSO_(4).5H_(2)O` is blue in colour while `CuSO_(4)` is colourless. Why ?A. presence of strong field ligand in `CuSO_(4) * 5H_(2)O`B. absence of water (ligand) , `d-d` transitions are not possible in `CuSO_(4)`C. anhydrous `CuSO_(4)` undergoes d-d transitions due to crystal field splittingD. colour is lost due to loss of unpaired electrons .

`CuSO_(4).5H_(2)O` is blue in colour while `CuSO_(4)` is colourless. W

1.	`CuSO_(4).5H_(2)O` is blue in colour while `CuSO_(4)` is colourless. Why ?A. presence of strong field ligand in `CuSO_(4) * 5H_(2)O`B. absence of water (ligand) , `d-d` transitions are not possible in `CuSO_(4)`C. anhydrous `CuSO_(4)` undergoes d-d transitions due to crystal field splittingD. colour is lost due to loss of unpaired electrons .
Answer» Correct Answer - A In `CuSO_(4) * 5H_(2)O` water acts as ligand and as a result it causes crystal field splitting making d-d transitions possible in `CuSO_(4) * 5H_(2)O` . Hence , it is coloured . In anhydrous `CuSO_(4)` , due to absence of ligand crystal field splitting is not possible hence no colour is observed .

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