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`DeltaG^(c-)` or the reaction is `,` `4Al+3O_(2)+6H_(2)O+4overset(c-)(O)H rarr 4 Al(OH)_(4)^(c-)` `E^(c-)._(cell)=2.73V` `Delta_(f)G^(c-)._((overset(c)(O)H))=-157k J mol^(-1)` `Delta_(f)G^(c-)._((overset(c-)(O)H))=-237k J mol^(-1)`A. `-3.16xx10^(3)kJ mol^(-1)`B. `-0.79xx10^(3)kJmol^(-1)`C. `-0.263xx10^(3)k J mol^(-1)`D. `+0.263xx10^(3)k J mol^(-1)` |
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Answer» Correct Answer - a `Delta_(r)G^(c-)._(cell)=-n_(cell)FE^(c-)._(cell)=-12xx96500xx2.73` `=-3.16xx10^(3)k J mol^(-1)` For `n_(cell)` write the half cell reaction as `:` Cathode `: 2H_(2)O(l)+O_(2)(g)+4e^(-) rarr 4 overset(c-)(O)H(aq)` Anode `:Al(s)+4overset(c-)(O)H(aq)rarr Al(OH)_(4)^(c-)(aq)+3e^(-)` |
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