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derive acceleration due to gravity |
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Answer» f is directly proportional to 1/d^2.......1F is directly proportional to Mm... ..2From 1and 2F is directly proportional to Mm/d^2Directly proportional change =gEarth mass 6*10power24. (M) Earth radius 6.4*10power6. (d^2)G=6.673*10power-11g=GMm/d^2g=6.7*10power-11*6*10power24/(6.4*10power6)^2g=9.8 As per Newton\'s law, Force = mass × acceleration = m×a .....................(1)where m is mass and a is accelerationGravitational force acting on a mass m on earth\'s surface = G (m×M)/R2 = m × GM/R2 ..........................(2)where G is Gravitational force constant, M is mass of earth and R is radius of earthBy comparing (1) and (2), acceleration due to gravity = a = (G×M)/R2 |
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