1.

Derive the relation between momentum and kinetic energy.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) <a href="https://interviewquestions.tuteehub.com/tag/consider-2017521" style="font-weight:bold;" target="_blank" title="Click to know more about CONSIDER">CONSIDER</a> an <a href="https://interviewquestions.tuteehub.com/tag/object-11416" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECT">OBJECT</a> of mass m moving with a velocity `vec(v)`. Then its linear momentum is `vec(p)=mvec(v)` and its kinetic energy, `KE1/2mv^(2)`. <br/> `KE=1/2mv^(2)=1/<a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>(vec(v).vec(v))"...(1)"` <br/> (ii) Multiplying both the numerator and denominator of equation (1) by mass, m <br/> `KE=1/2(m^(2)(vec(v).vec(v)))/m` <br/> `=1/2((mvec(v)).(mvec(v)))/m[vec(p)=mvec(v)]` <br/> `=1/2(vec(p)*vec(p))/m` <br/> `=p^(2)/(2m), KE=p^(2)/(2m)` <br/> (iii) where `abs(vec(p))` is the magnitude of the momentum. The magnitude of the linear momentum can be <a href="https://interviewquestions.tuteehub.com/tag/obtained-7273275" style="font-weight:bold;" target="_blank" title="Click to know more about OBTAINED">OBTAINED</a> by <br/> `abs(vec(p))=p=sqrt(2m(KE))` <br/> (iv) Note that if kinetic energy and mass are given, only the magnitude of the momentum can be calculated but not the direction of momentum. It is because the kinetic energy and mass are scalars.</body></html>


Discussion

No Comment Found

Related InterviewSolutions