InterviewSolution
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InterviewSolution
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Describe a simple test to distinguish between the following pairs of compounds (i) (A) `[Co(NH_(3))_(5)Br]SO_(4)` and (B) `[Co(NH_(3))_(5)SO_(4)]Br` (ii) (A) `[Cr(H_(2)O)_(6)]CI_(3)` and `(B) [Cr (H_(2)O)_(5)CI] CI_(2)H_(2)O` (iii) (A) `cis [PtCI_(2)(NH_(3))_(2)]` and (B) trans `[Pt CI_(2)(NH_(3))_(2)]` (iv) (A) and (B) Two enantiomers of `[Co(en)_(2)(NH_(3))_(2)]` (V) (A) (A) `[Cr (NH_(3))_(6)][Cr(NH_(3))_(2)(NO_(2))_(4)]` (vi) (A) `[Pt(NH_(3))_(2)CI_(2)]` and (B) `[Pt(NH_(3))_(6)]CI_(2)` (vii) (A) `[Co(NH_(3))_(5)CI]SO_(4)` and (B) `[Co(NH_(3))_(5)SO_(4)]CI` . |
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Answer» (A) and (B) are distinguished by qualitative method (A) give white precipitate of `BaSO_(4)` with `BaCI_(2)` solution due to the presence of `SO^(2-)_(4)` as counter ion (B) gives pale yellow precipitate of AgBr `("partially soluble in" NH_(4)OH)` with `AgHO_(3)` solution due to the presence of `Br^(Θ)` ion as counter ion (ii) (A) and (B) are distinguished by conductance method (A) give 4 ions with high charge whereas (B) gives 3 ions with low in aqueous solution as show `Ararr underset(4 ionss (+3)` and-(3)char g e)(ubrace([Cr(H_(2)O)_(6)]^(3+)+3CI^(Θ)` `Brarr underset(4 ionss (+2 and-2)char g e)(ubrace([Cr(H_(2)O)_(5)]^(2+)+2CI^(Θ))` So conductance of (A) will be higher than that of B Further (A) and (B) are also distinguished by quantitative method with `AgNO_(3)` (A) and (B) gives a white precipitate of AgCI in the presence of 3and 2 moles of `CI^(Θ)` as counter ions (iii) (A) cis `[PtCI_(2)(NH_(3))_(2)]` has some value of dipole moment while the (B) tran `[PtCI_(2)(NH_(3))_(2)]` has zero value for its dipole moment (iv) One enantiomer of `[Co(en)_(2)CI_(2)]^(o+)` is dextrorotatory (d -form) and the other enantiomer is levorotatory (l -form) (v) The give isomers can be distinguished by conductivity measurement (A) conducts as `(3 + ,3-)` electrolyte while (B) conducts as `(1 +1,1-)` electrolyte `(A)rarrunderset((3+,3-)el ectroyte)([Cr(NH_(3))_(6)]^(3+))+[Cr(NO_(2))_(6)]^(3-)` (B) `rarr underset((1+,1-) "el ectrolyte")([Cr(NH_(3))_(4)(NO_(2))_(2)]^(o+))+[Cr(NH_(3))_(2)(NO_(2))_(4)]^(o+)` Thus (A) has higher value of molar conductane than (B) (vi) `(A)` and (B) can be distinguished by conductance method The ionisation of the give complex compounds can be shown as (A) `rarr` No ions (B) `rarr underset(three ions)ubrace([Pt(NH_(3))_(6)]^(3+)+2CI^(Θ))` Therefore (A) has zero value of its electrolytic conductane whereas `(B)` gives 3 ions it has some value of electrolytic conductane (vii) (A) and `(B)` are distinguished by qualitative method `(A)` gives white precipitate of `BaSO_(4)` with `BaCI_(2)` solution due to presence of `SO_(4)^(-2)` ion as counter ion `(B)` gives white precipitate of AgCI (soluble in `NH_(4)OH)` with `AgNO_(3)` solution due to the presence of `CI^(o+)` ion as counter ion . |
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