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Determine `DeltaG^(0)` for the button cell used in the watches. The cell reactions is `Zn_((s))+Ag _(2)O_((s))H_(2)O _((l))to Zn_((aq))^(2+)+2 Ag _((s))+2OH_((aq))^(-)` `E_(Ag^(+)//Ag)^(0) =+0.80V,E_(Zn^(2+)//Zn)^(0)=-0.76V.` |
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Answer» Given `E^(0) of Ag^(+)//Ag =0.80 V` `E^(0) of Z n ^(+2)//Zn =-0.76V` Cell representation `Zn //Zn^(+2)||Ag^(+)//Ag` `EMF=E_(RHS)-E_(LHS) =0.80-(-0.76)=1.56V` `DeltaG=-nFE^(0)=-2xx96500xx1.53=-301.08kJ//"mole"` |
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