Determine the equilibrium constant of the following reaction at 298 K : `2Fe^(3+)+Sn^(2+) rarr 2Fe^(2+) +Sn^(4+)` `("Given: "E_(Sn^(4+)//Sn^(2+))^(@)=0.15" volt, "E_(Fe^(3+)//Fe^(2+))^(@)=0.771" volt"` )

Determine the equilibrium constant of the following reaction at 298 K

1.	Determine the equilibrium constant of the following reaction at 298 K : `2Fe^(3+)+Sn^(2+) rarr 2Fe^(2+) +Sn^(4+)` `("Given: "E_(Sn^(4+)//Sn^(2+))^(@)=0.15" volt, "E_(Fe^(3+)//Fe^(2+))^(@)=0.771" volt"` )
Answer» Correct Answer - `K=1.0xx10^(21)` Calculate `E_(cell)^(@)`. The value is 0.21 volt. Apply `E_(cell)^(@)=0.0591/2 log K`

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What are elementary reactions ?

Determine the equilibrium constant of the following reaction at 298 K : `2Fe^(3+)+Sn^(2+) rarr 2Fe^(2+) +Sn^(4+)` `("Given: "E_(Sn^(4+)//Sn^(2+))^(@)=0.15" volt, "E_(Fe^(3+)//Fe^(2+))^(@)=0.771" volt"` )

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