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Determine the number of ways such that 5 men and 5 women be seated at a round table if no two women are seated together.(a) 654870(b) 144521(c) 362160(d) 5634I have been asked this question during an interview.The origin of the question is Counting in section Counting of Discrete Mathematics

Answer» RIGHT option is (c) 362160

To elaborate: The men and women can be seated alternately so that no TWO women will sit together. Hence, 4 women can be seated on alternate seats at a round table in (4 – 1)! or 6

ways. Now, the 5 men can be seated in the remaining seats in 5! or 120 ways. THEREFORE the total number of ways in this case will be (10-1)! – (120 * 6) = 362160.


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