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Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation: N2 (g) + H2 (g)→ 2NH3 (g) Calculate the mass of ammonia produced if 308 g dinitrogen reacts with 25 g of dihydrogen. |
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Answer» N2(g) + 3H2(g) →2NH3(g)28g 6g 34g 28 g of N2 REACTS with 6g of H2. 1g of N2 reacts with 6/28 g of H2 2000g of N2 will react with 2000 × 6/28 = 428.57 of H2 but H2 is given 1 × 10³g is greater than 428.57 g N2 is a limiting reagent and limits the production of ammonia 28g of N2 produces 34 g of NH3 1g of N2 produces 34/28 g of NH3 2000g of N2 will produce 34/28 × 2000 = 2428.57 g of NH3. (ii) H2 is excess so it remains unreacted (iii) Mass of unreacted dihydrogen = 1000-428.57 =571.43gExplanation: I hope this is correct |
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